Textbook solutions - Mathematics Part - I - Class 10 - Maharashtra State Board

Fill in the blank with correct number

$\begin{vmatrix} 3 & 2 \\ 4 & 5 \end{vmatrix}$

= $3 \times \fbox{\phantom{long}} - \fbox{\phantom{long}} \times 4$

= $\fbox{\phantom{long}} - 8$

= $\fbox{\phantom{long}}$

Find the value of following determinants.

$\begin{vmatrix} -1 & 7 \\ 2 & 4 \end{vmatrix}$

$\begin{vmatrix} 5 & 3 \\ -7 & 0 \end{vmatrix}$

$\begin{vmatrix} \dfrac{7}{3} & \dfrac{5}{3} \\ \\ \dfrac{3}{2} & \dfrac{1}{2} \end{vmatrix}$

Solve the following simultaneous equations using Cramer's rule.

$3x - 4y =10$ ; $4x + 3y = 5$

4x + 3y - 4 = 0 ; 6x = 8 - 5y

x + 2y = -1 ; 2x - 3y = 12

6x - 4y = -12 ; 8x - 3y = -2

4m + 6n = 54 ; 3m + 2n = 28

2x + 3y = 2 ; x - $\dfrac{y}{2}$ = $\dfrac{1}{2}$