Complete the following activity to solve the simultaneous equation.

5x + 3y = 9 ................(I)

2x - 3y = 12 ................(II)

Let's add equation (I) & (II)

$\dfrac{\begin{aligned} 5x + 3y &= 9 \\ \mathop{+}\mkern40mu 2x - 3y &= 12 \mkern60mu \end{aligned}}{\fbox{\phantom{lon}}x = 21}$

x = $\frac{\fbox{\phantom{long}}}{\fbox{\phantom{long}}}$

x = $\fbox{\phantom{long}}$

place x = 3 in equation (I)

5 x $\fbox{\phantom{long}}$ + 3y = 9

3y = 9 - $\fbox{\phantom{long}}$

3y = $\fbox{\phantom{long}}$

y = $\dfrac{\fbox{-6}}{3}$

Y = $\fbox{\phantom{long}}$

∴ Solution is (x,y) = ( $\fbox{\phantom{long}}$ , $\fbox{\phantom{long}}$ )

Solve the following simultaneous equation.